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发表于 2006-10-17 02:23:23
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解枪数和分数& w+ p% v0 w0 `! R7 X0 \
分数 解枪数
- T( x) Z/ D' r>= 200000 140 a k' {) P, j5 t$ M3 p; Y8 r
>= 140000 13, q- y7 |& x0 M, \, h7 P
>= 120000 12
, b* Y8 i/ k# r' A>= 100000 11
7 c6 X: a$ e4 K1 n/ I$ d G>= 80000 10
7 n; y g- p N& g1 ~$ m# n$ v>= 60000 9
( F0 s4 {' M0 ^* }3 C$ Q>= 40000 8
7 i3 p" N k& u. P4 x+ ?>= 25000 7' S* W: {( z# N) Q
>= 15000 6% ]$ [) G0 ~' D4 z0 z
>= 9000 5
' n; J4 O @4 R) \. r>= 5000 4
- \0 a: y! O# Z! S4 |>= 2000 3
. O& b; i- P5 o' |: ^7 U9 _>= 800 2
+ `7 m3 {" k" R0 k- z9 Y>= 200 1
* F+ I# K; _/ f3 L- q+ n2 Z8 r$ W+ N8 W4 ^& O
.......! ]. q4 v ^+ ^% F- o/ Q( A8 w
为什么这样啊... 太复杂了. 用BF2的分数/解枪数不行吗?
0 N+ B( |, L4 i. J% Y" e- N" {2 \
5 K4 g5 z- {8 S$ ?* U3 n0 [Rank2: 1 unlock# N! P4 U" [4 k, j3 e
Rank3: 1 unlock
' u, r: ?% @: c7 JRank4: 2 unlock (1 unlock if no SF)(Rank4可以开始用SF武器)
% T0 `. r* B1 x. O% p4 ~- A* ZRank5: 2 unlock (1 unlock if no SF)
2 S& Q7 C, j2 x8 _. o: }" R4 hRank6: 2 unlock (1 unlock if no SF)
) [' n! m0 G* O- qRank7: 2 unlock (1 unlock if no SF), Z* z* L& c! Z* G+ ~0 P
Rank8: 2 unlock (1 unlock if no SF)
, ^! X3 }2 b5 I$ C, A7 X1 {Rank(...): 2 unlock. (1 unlock if no SF)
6 |* h8 `. ]" t/ s5 G/ H3 q3 u- m9 g" t6 B5 k$ D0 |& o" Q
[ 本帖最后由 Genome852 于 2006-10-17 20:56 编辑 ] |
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