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发表于 2006-10-17 02:23:23
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解枪数和分数7 w5 q+ @$ i( S3 d7 D1 a
分数 解枪数
6 A6 a( D7 j# x6 P) n. B, j>= 200000 147 Z6 Z. k5 `0 ^5 v. v% N1 k
>= 140000 13, J5 A) L: `1 H! P7 R' D
>= 120000 12
+ j4 L7 ~( P+ T2 n# m+ o>= 100000 11
4 a1 c# p. h7 I6 \5 W>= 80000 104 F y: o4 U8 u
>= 60000 9
- J$ }( c8 z( ^7 V! D2 `, P>= 40000 8
& {- g. y5 @3 a3 I6 y5 x7 O>= 25000 7; k0 `% ?6 y6 ?0 O; j
>= 15000 6
, i3 @ O, e* L- G7 _4 [9 J>= 9000 5 e& J8 p- s1 W( `
>= 5000 4
2 l6 }& T/ D1 w& z1 U& W>= 2000 3
" k1 M8 \/ x' I d$ j# e>= 800 2, @; p! K4 d m( @+ R
>= 200 1
/ `! R# H, G( |1 Z6 s, r
6 z! C9 M" X" Q) E.......: b @' A2 r- {% D$ O
为什么这样啊... 太复杂了. 用BF2的分数/解枪数不行吗?
1 V% Z9 H) ~/ E% ]7 [5 w& l
) G- i) u1 P8 ]/ C$ v8 Y) J0 Q1 uRank2: 1 unlock
9 d3 G7 u l8 O4 x; [$ j8 mRank3: 1 unlock
E) {; {6 D. {7 CRank4: 2 unlock (1 unlock if no SF)(Rank4可以开始用SF武器); A# V& g1 O- [0 S
Rank5: 2 unlock (1 unlock if no SF)" v7 R4 Z( f' Z9 s& e! f( r: k
Rank6: 2 unlock (1 unlock if no SF)
% G! u, K6 L: K4 w: t, F6 wRank7: 2 unlock (1 unlock if no SF)" ]' }6 Y" W! O# ]7 M2 P1 Q3 {' ]
Rank8: 2 unlock (1 unlock if no SF)
) e" }4 r0 F& r: R* Z* K* VRank(...): 2 unlock. (1 unlock if no SF)* i [% ^% B: p
7 R0 S' Q$ Q% `5 @/ R[ 本帖最后由 Genome852 于 2006-10-17 20:56 编辑 ] |
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